10x^2-2200x+100000=0

Solution for 10x^2-2200x+100000=0 equation:

10x^2-2200x+100000=0

a = 10; b = -2200; c = +100000;
Δ = b2-4ac
Δ = -22002-4·10·100000
Δ = 840000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{840000}=\sqrt{40000*21}=\sqrt{40000}*\sqrt{21}=200\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2200)-200\sqrt{21}}{2*10}=\frac{2200-200\sqrt{21}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2200)+200\sqrt{21}}{2*10}=\frac{2200+200\sqrt{21}}{20}
$